HLTH 7025 Healthcare Data for Decision-Making, Spring 2022
\nAssignment 3 (Due Monday, November 7, 2022)
\nPlease answer all 2 questions. Record your answers in the template document provided and submit them via Turnitin before 11:59 pm on the due date. The marks allocated to each question are shown in the assignment. A total of 40 marks are available, and this assignment is worth 40% of your overall grade.
\nCopying answers from other students, sharing answers with other students, and writing answers in a group are all forms of cheating. Any student doing any of these will be reported for academic misconduct.
\nQuestion 1 [15 marks]
\nFrom a cross-sectional life table of age-specific death rates provided, please answer the following questions below:
\nAge group Interval Death Population Death rate nQx lx ndx Lx Tx ex
\n0-4 24 14524 1000
\n5-9 1 17816
\n10-14 3 24172
\n15-19 15 20848
\n20-24 20 10884
\n25-29 11 7212
\n30-34 11 9136
\n35-39 8 12868
\n40-44 20 14132
\n45-49 22 10128
\n50-54 30 6784
\n55-59 37 5740
\n60-64 57 4048
\n65-69 65 2772
\n70-74 107 2100
\n75-79 74 1136
\n80-84 69 440
\n85-89 41 168
\n90+ 17 44 1
\n(a) Calculate the following column heading: interval, Death rate, nQx, lx, ndx ,Lx ,Tx and ex [12 marks]
\n(b) To what age would you expect a person to live (on average) once he\/she attained the age of 15 years? [3 marks]
\nQuestion 2 [25 marks]: (b) At what age would you expect a person to live (on average) after reaching the age of 15? [3 marks]
\nQuestion 2 (25 points):
\nFor 15 years, a large hospital in Nepal monitored men with prostate cancer. The data is summarized in two tables below, which differentiate patients based on treatment status (with and without chemotherapy) and provide the information required to calculate cumulative survival probabilities.
\nTable 1: Chemotherapy patents
\nA large hospital in Nepal followed up with men with prostate cancer for 15 years. The data is summarised in two tables below, differentiating patients according to treatment status (With and without chemotherapy) and providing the necessary information to calculate the cumulative survival probabilities.
\nTable 1: Patents with chemotherapy
\nYears Number at Risk Death Cumulative Survival probability
\n1 21 0
\n2 0
\n3 0
\n4 0
\n5 1
\n6 1
\n7 1
\n8 0
\n9 0
\n10 0
\n11 0
\n12 1
\n13 1
\n14 0
\n15 0
\nTable 2: Patents without chemotherapy
\nYears Number at Risk Death Cumulative Survival probability
\n1 28 1
\n2 2
\n3 1
\n4 1
\n5 0
\n6 0
\n7 0
\n8 1
\n9 1
\n10 2
\n11 1
\n12 2
\n13 0
\n14 1
\n15 1
\n\u2022 Calculate the cumulative survival probabilities for the two treatment groups [9 marks]
\n\u2022 Draw a graph showing both cumulative survival probabilities? [2 marks]
\n\u2022 Investigate the two survival probabilities curves carefully. For survival benefits, suggest whether it would be beneficial for a patient to accept chemotherapy or not. and why? [2 marks]
\n\u2022 Compare the two groups of patients by means of a log-rank test (a=0.05; two-sided) [12 marks]<\/p>\n","protected":false},"excerpt":{"rendered":"
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